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Q. A straight wire having mass of $1.2\, kg$ and length of $1 \,m$ carries a current of $5 \,A$. If the wire is suspended in mid-air by a uniform horizontal magnetic field, then the magnitude of field is

Moving Charges and Magnetism

Solution:

For mid-air suspension the upward force $F$ on wire due to magnetic field $B$ must be balanced by the force due to gravity, then
$IlB=mg; B=\frac{mg}{Il}$
Here, $m=1.2 \, kg$,
$g=10\,m\,s^{-2}, I=5\,A$,
$l=1\,m$
$B=\frac{1.2\times10}{5\times1}$
$=2.4\,T$