A stone is thrown upwards with a velocity 50 ms-1. Another stone is simultaneously thrown downwards from the same location with a velocity 50 ms-1. When the first stone is at the highest point, the velocity of the second stone is (Take g = 10 ms-2):

Question

A stone is thrown upwards with a velocity 50 ms-1. Another stone is simultaneously thrown downwards from the same location with a velocity 50 ms-1. When the first stone is at the highest point, the velocity of the second stone is (Take g = 10 ms-2): (A) Zero (B) 50 ms-1 (C) 100 ms-1 (D) 150 ms-1

Tardigrade Admin · Accepted Answer

t = (50/g) = (50/10) = 5 s v = -50 - 10 × 5 = - 100 m/s

Q. A stone is thrown upwards with a velocity $50 m s^{- 1}$ . Another stone is simultaneously thrown downwards from the same location with a velocity $50 m s^{- 1}$ . When the first stone is at the highest point, the velocity of the second stone is (Take $g = 10 m s^{- 2})$ :

Zero

$50 m s^{- 1}$

$100 m s^{- 1}$

$150 m s^{- 1}$

$t = \frac{50}{g} = \frac{50}{10} = 5 s$

$v = - 50 - 10 \times 5$

$= - 100 m / s$

Q. A stone is thrown upwards with a velocity 50ms−1. Another stone is simultaneously thrown downwards from the same location with a velocity 50ms−1. When the first stone is at the highest point, the velocity of the second stone is (Take g=10ms−2):

Zero

50ms−1

100ms−1

150ms−1

t=g50​=1050​=5s v=−50−10×5 =−100m/s

Q. A stone is thrown upwards with a velocity $50 m s^{- 1}$ . Another stone is simultaneously thrown downwards from the same location with a velocity $50 m s^{- 1}$ . When the first stone is at the highest point, the velocity of the second stone is (Take $g = 10 m s^{- 2})$ :

$50 m s^{- 1}$

$100 m s^{- 1}$

$150 m s^{- 1}$

$t = \frac{50}{g} = \frac{50}{10} = 5 s$

$v = - 50 - 10 \times 5$

$= - 100 m / s$