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Q. A stone is thrown upwards with a velocity $50 \,ms^{-1}$. Another stone is simultaneously thrown downwards from the same location with a velocity $50 \,ms^{-1}$. When the first stone is at the highest point, the velocity of the second stone is (Take $g = 10 \,ms^{-2})$:

Motion in a Straight Line

Solution:

$t = \frac{50}{g} = \frac{50}{10} = 5\,s$
$v = -50 - 10 \times 5$
$ = - 100 \,m/s$