A standard filament lamp consumes 100 W when connected to 200 V ac mains supply. The peak current through the bulb will be :

Question

A standard filament lamp consumes 100 W when connected to 200 V ac mains supply. The peak current through the bulb will be : (A) 0.707 A (B) 1 A (C) 1.414 A (D) 2 A

Tardigrade Admin · Accepted Answer

I text rms V text rms = P I text rms × 200=100 I text rms =(1/2) So, I text peak =I text rms √2 =(1/2) × √2 =(1/√2)=0.707 A

Q. A standard filament lamp consumes $100 W$ when connected to $200 V$ ac mains supply. The peak current through the bulb will be :

$0.707 A$

$1 A$

$1.414 A$

$2 A$

$I_{rms} V_{rms} = P$
$I_{rms} \times 200 = 100$
$I_{rms} = \frac{1}{2}$
So, $I_{peak} = I_{rms} 2$
$= \frac{1}{2} \times 2$
$= \frac{1}{2} = 0.707 A$

Q. A standard filament lamp consumes 100W when connected to 200V ac mains supply. The peak current through the bulb will be :

0.707A

1A

1.414A

2A