A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v1 ms-1 and v2 ms-1 respectively making angles of 30Â° and 60Â° with respect to the original direction of motion of A. The ratio (v1/v2) will be

Question

A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v1 ms-1 and v2 ms-1 respectively making angles of 30Â° and 60Â° with respect to the original direction of motion of A. The ratio (v1/v2) will be (A) (√3/4) (B) (4/√3) (C) (1/√3) (D) √3

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/01d94d3a8250163a9b5f37bbac8c397f-.png" /> Along y-axis momentum remains zero. Here 4 v1 sin 30° =v2 sin 60° (v1/v2) =(√3/4)

$\frac{3}{4}$

$\frac{4}{3}$

$\frac{1}{3}$

$3$

Along $y$ -axis momentum remains zero. Here
$4 v_{1} sin 3 0^{\circ} = v_{2} sin 6 0^{\circ}$
$\frac{v _{1}}{v _{2}} = \frac{3}{4}$

43​​

3​4​

3​1​

3​

Along y-axis momentum remains zero. Here 4v1​sin30∘=v2​sin60∘ v2​v1​​=43​​

$\frac{3}{4}$

$\frac{4}{3}$

$\frac{1}{3}$

$3$

Along $y$ -axis momentum remains zero. Here
$4 v_{1} sin 3 0^{\circ} = v_{2} sin 6 0^{\circ}$
$\frac{v _{1}}{v _{2}} = \frac{3}{4}$