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Q. A spherical ball $A$ of mass $4\,kg$, moving along a straight line strikes another spherical ball $B$ of mass $1\,kg$ at rest. After the collision, $A$ and $B$ move with velocities $v_{1}\, ms^{-1}$ and $v_{2}\, ms^{-1}$ respectively making angles of $30°$ and $60°$ with respect to the original direction of motion of $A$. The ratio $\frac{v_{1}}{v_{2}}$ will be

WBJEEWBJEE 2012Work, Energy and Power

Solution:

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Along $y$-axis momentum remains zero. Here
$4 v_{1} \sin 30^{\circ} =v_{2} \sin 60^{\circ}$
$\frac{v_{1}}{v_{2}} =\frac{\sqrt{3}}{4}$