A sound wave of frequency 440 Hz is passing through air. An O 2 molecule (mass =5.3 × 10-26 kg ) is set in oscillation with an amplitude of 10-6 m speed at the centre of its oscillation is:

Question

A sound wave of frequency 440 Hz is passing through air. An O 2 molecule (mass =5.3 × 10-26 kg ) is set in oscillation with an amplitude of 10-6 m speed at the centre of its oscillation is: (A) 1.70 × 10-5 m / s (B) 17.0 × 10-5 m / s (C) 2.76 × 10-5 m / s (D) 2.77 × 10-5 m / s

Tardigrade Admin · Accepted Answer

v max =ωn A =(2 π f) A=(2 π)(440)(10-6) =2.76 × 10-5 m / s

Q. A sound wave of frequency $440 Hz$ is passing through air. An $O_{2}$ molecule (mass $= 5.3 \times 1 0^{- 26} k g$ ) is set in oscillation with an amplitude of $1 0^{- 6} m$ speed at the centre of its oscillation is:

$1.70 \times 1 0^{- 5} m / s$

$17.0 \times 1 0^{- 5} m / s$

$2.76 \times 1 0^{- 5} m / s$

$2.77 \times 1 0^{- 5} m / s$

$v_{m a x} = ω_{n} A$
$= (2 π f) A = (2 π) (440) (1 0^{- 6})$
$= 2.76 \times 1 0^{- 5} m / s$

Q. A sound wave of frequency 440Hz is passing through air. An O2​ molecule (mass =5.3×10−26kg ) is set in oscillation with an amplitude of 10−6m speed at the centre of its oscillation is:

1.70×10−5m/s

17.0×10−5m/s

2.76×10−5m/s

2.77×10−5m/s