Question

A sound wave of frequency $440\, Hz$ is passing through air. An $O _{2}$ molecule (mass $=5.3 \times 10^{-26} kg$ ) is set in oscillation with an amplitude of $10^{-6} m$ speed at the centre of its oscillation is:

• A. $1.70 \times 10^{-5} m / s$
• B. $17.0 \times 10^{-5} m / s$
• C. $2.76 \times 10^{-5} m / s$
• D. $2.77 \times 10^{-5} m / s$

Answer 1

Answer: (C)

$v_{\max } =\omega_{n} A$
$=(2 \pi f) A=(2 \pi)(440)\left(10^{-6}\right)$
$=2.76 \times 10^{-5} m / s$