A solution of a compound X in dilute HCl on treatment with a solution of BaCl2 gives a white precipitate of a compound Y which is insoluble in cone. HNO3 and conc. HCl. Compound X imparts golden yellow colour to the flame. underset text(imparts golden yellow colour)X text(Solution in dilute HCl) +BaCl2 arrow underset textWhit pptY xrightarrow[ textConc.HCl] textConc. HNO3 Insolubl What are compounds X and Y ?

Question

A solution of a compound X in dilute HCl on treatment with a solution of BaCl2 gives a white precipitate of a compound Y which is insoluble in cone. HNO3 and conc. HCl. Compound X imparts golden yellow colour to the flame. underset text(imparts golden yellow colour)X text(Solution in dilute HCl) +BaCl2 arrow underset textWhit pptY xrightarrow[ textConc.HCl] textConc. HNO3 Insolubl What are compounds X and Y ? (A) X is MgCl2 and Y is BaSO4 (B) X is CaCl2 and Y is BaSO4 (C) X is Na2SO4 and Y is BaSO4 (D) X is MgSO4 and Y is BaSO4

Tardigrade Admin · Accepted Answer

underset text(X)Na2SO4+BaCl2 → underset text(Y)BaSO4 +2NaCl

$X$ is $M g C l_{2}$ and $Y$ is $B a S O_{4}$

$X$ is $C a C l_{2}$ and $Y$ is $B a S O_{4}$

$X$ is $N a_{2} S O_{4}$ and $Y$ is $B a S O_{4}$

$X$ is $M g S O_{4}$ and $Y$ is $B a S O_{4}$

$(X) N a_{2} S O_{4} + B a C l_{2} \to (Y) B a S O_{4} + 2 N a Cl$

X is MgCl2​ and Y is BaSO4​

X is CaCl2​ and Y is BaSO4​

X is Na2​SO4​ and Y is BaSO4​

X is MgSO4​ and Y is BaSO4​

(X)Na2​SO4​​+BaCl2​→(Y)BaSO4​​+2NaCl

$X$ is $M g C l_{2}$ and $Y$ is $B a S O_{4}$

$X$ is $C a C l_{2}$ and $Y$ is $B a S O_{4}$

$X$ is $N a_{2} S O_{4}$ and $Y$ is $B a S O_{4}$

$X$ is $M g S O_{4}$ and $Y$ is $B a S O_{4}$

$(X) N a_{2} S O_{4} + B a C l_{2} \to (Y) B a S O_{4} + 2 N a Cl$