Question

A solution of a compound $X$ in dilute $HCl$ on treatment with a solution of $BaCl_2$ gives a white precipitate of a compound $Y$ which is insoluble in cone. $HNO_3$ and conc. $HCl$. Compound $X$ imparts golden yellow colour to the flame.
$\underset{\text{(imparts golden yellow colour)}}{X \text{(Solution in dilute HCl) }} +BaCl_2 \rightarrow\underset{\text{Whit ppt}}{Y} \xrightarrow[\text{Conc}.HCl]{\text{Conc}. HNO_3}$ Insolubl
What are compounds $X$ and $Y$ ?

• A. $X$ is $MgCl_2$ and $Y$ is $BaSO_4$
• B. $X$ is $CaCl_2$ and $Y$ is $BaSO_4$
• C. $X$ is $Na_2SO_4$ and $Y$ is $BaSO_4$
• D. $X$ is $MgSO_4$ and $Y$ is $BaSO_4$

Answer 1

Answer: (C)

$\underset{\text{(X)}}{Na_2SO_4}+BaCl_2 \to \underset{\text{(Y)}}{BaSO_4} +2NaCl$