A solution is obtained by mixing 300 g of 25 % and 400 g of 40 % solution by mass. The percentage of solute in the final solution is

Question

A solution is obtained by mixing 300 g of 25 % and 400 g of 40 % solution by mass. The percentage of solute in the final solution is (A) 23 % (B) 50 % (C) 33.5 % (D) 66.5 %

Tardigrade Admin · Accepted Answer

300 g of 25 % solution contains solute = 75 g 400 g of 40 % solution contains solute = 160 g Total solute = 160 + 75 = 235 g Total solution = 300 + 400 = 700 g % of solute in the final solution = (235/700) × 100 = 33.5 %

Q. A solution is obtained by mixing $300 g$ of $25%$ and $400 g$ of $40%$ solution by mass. The percentage of solute in the final solution is

$23%$

$50%$

$33.5%$

$66.5%$

$300 g$ of $25%$ solution contains solute $= 75 g$
$400 g$ of $40%$ solution contains solute $= 160 g$
Total solute $= 160 + 75 = 235 g$
Total solution $= 300 + 400 = 700 g$
$%$ of solute in the final solution $= \frac{235}{700} \times 100 = 33.5%$

Q. A solution is obtained by mixing 300g of 25% and 400g of 40% solution by mass. The percentage of solute in the final solution is

23%

50%

33.5%

66.5%