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Q. A solution is obtained by mixing $300\, g$ of $25\%$ and $400\, g$ of $40\%$ solution by mass. The percentage of solute in the final solution is

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Solution:

$300\, g$ of $25\%$ solution contains solute $= 75\, g$
$400\, g$ of $40\%$ solution contains solute $ = 160\, g$
Total solute $ = 160 + 75 = 235\, g$
Total solution $ = 300 + 400 = 700\, g$
$\%$ of solute in the final solution $= \frac{235}{700} \times 100 = 33.5\%$