A solution is obtained by mixing 200 g of 30 % and 300 g of 20 % solution by weight. What is the percentage of solute in the final solution?

Question

A solution is obtained by mixing 200 g of 30 % and 300 g of 20 % solution by weight. What is the percentage of solute in the final solution? (A) 50 % (B) 28 % (C) 64 % (D) 24 %

Tardigrade Admin · Accepted Answer

Mass of solute =( % text weight × text mass of solvent /100) Mass of solute in 200 g of 30 % solution =60 g Mass of solute in 300 g of 20 % solution =60 g total solute mass =120 g total solvent mass =500 g operatornamemass %=(120/500) × 100=24 %

Q. A solution is obtained by mixing $200 g$ of $30%$ and $300 g$ of $20%$ solution by weight. What is the percentage of solute in the final solution?

$50%$

$28%$

$64%$

$24%$

Mass of solute $= \frac{% weight \times mass of solvent}{100}$
Mass of solute in $200 g$ of $30%$ solution $= 60 g$
Mass of solute in $300 g$ of $20%$ solution $= 60 g$
total solute mass $= 120 g$
total solvent mass $= 500 g$
$mass % = \frac{120}{500} \times 100 = 24%$

Q. A solution is obtained by mixing 200g of 30% and 300g of 20% solution by weight. What is the percentage of solute in the final solution?

50%

28%

64%

24%