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Q.
A solution is obtained by mixing $200\, g$ of $30\%$ and $300\, g$ of $20\%$ solution by weight. What is the percentage of solute in the final solution?
Solutions
Solution:
Mass of solute $=\frac{\% \text { weight } \times \text { mass of solvent }}{100}$
Mass of solute in $200 g$ of $30 \%$ solution $=60 g$
Mass of solute in $300 g$ of $20 \%$ solution $=60 g$
total solute mass $=120 g$
total solvent mass $=500 g$
$\operatorname{mass} \%=\frac{120}{500} \times 100=24 \%$