Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
A solid rectangular brick is to be made from 1 cu feet. of clay. The brick must be 3 times as long as it is wide. The ratio of height to width of the brick for which it will have minimum surface area, is
Q. A solid rectangular brick is to be made from 1 cu feet. of clay. The brick must be 3 times as long as it is wide. The ratio of height to width of the brick for which it will have minimum surface area, is
1985
149
Application of Derivatives
Report Error
A
9
2
B
(
9
2
)
3
1
C
3
2
D
2
3
Solution:
3
x
2
h
=
1
S
=
2
(
h
x
+
3
x
2
+
3
x
h
)
S
=
2
(
3
x
2
+
4
h
x
)
=
2
(
3
x
2
+
4
x
⋅
3
x
2
1
)
S
(
x
)
=
2
(
3
x
2
+
3
x
4
)
S
′
(
x
)
=
2
(
6
x
+
3
x
2
4
)
=
0
;
x
3
=
9
2
⇒
x
=
(
9
2
)
3
1
now
h
=
3
x
2
1
;
hence
x
h
=
3
x
2
1
⋅
x
1
=
3
x
3
1
=
3
⋅
2
1
⋅
9
=
2
3