A solid cube of copper of edge 10 cm subjected to a hydraulic pressure of 7 × 106 pascal. If Bulk modulus of copper is 140 GPa, then contraction in its volume will be

Question

A solid cube of copper of edge 10 cm subjected to a hydraulic pressure of 7 × 106 pascal. If Bulk modulus of copper is 140 GPa, then contraction in its volume will be (A) 5 × 10-8 m 3 (B) 4 × 10-8 m 3 (C) 2 × 10-6 m 3 (D) 108 m 3

Tardigrade Admin · Accepted Answer

Initial volume V=( text side )3=(10 × 10-2)3 P=7 × 106 Pa B=140 × 109 Pa We know (-Δ V/V)=(P/B) -Δ V= text Contraction in volume (-Δ V/10-3)=(7 × 106/140 × 109) -Δ V=5 × 10-8 m 3

Q. A solid cube of copper of edge $10 c m$ subjected to a hydraulic pressure of $7 \times 1 0^{6}$ pascal. If Bulk modulus of copper is $140 GP a$ , then contraction in its volume will be

$5 \times 1 0^{- 8} m^{3}$

$4 \times 1 0^{- 8} m^{3}$

$2 \times 1 0^{- 6} m^{3}$

$1 0^{8} m^{3}$

Q. A solid cube of copper of edge 10cm subjected to a hydraulic pressure of 7×106 pascal. If Bulk modulus of copper is 140GPa, then contraction in its volume will be

5×10−8m3

4×10−8m3

2×10−6m3

108m3

Initial volume V=( side )3=(10×10−2)3 P=7×106Pa B=140×109Pa We know V−ΔV​=BP​ {−ΔV= Contraction in volume } 10−3−ΔV​=140×1097×106​ −ΔV=5×10−8m3

Q. A solid cube of copper of edge $10 c m$ subjected to a hydraulic pressure of $7 \times 1 0^{6}$ pascal. If Bulk modulus of copper is $140 GP a$ , then contraction in its volume will be

$5 \times 1 0^{- 8} m^{3}$

$4 \times 1 0^{- 8} m^{3}$

$2 \times 1 0^{- 6} m^{3}$

$1 0^{8} m^{3}$