A solid AB has NaCl type structure with edge length 580.4 pm. The radius of A+ is 100 pm. What is the radius of B- in pm?

Question

A solid AB has NaCl type structure with edge length 580.4 pm. The radius of A+ is 100 pm. What is the radius of B- in pm? (A) 190.2 (B) 540.13 (C) 525 (D) 78.12

Tardigrade Admin · Accepted Answer

NaCl has fcc structure and thus, rc+ra=(a/2) 100+ra=(580 . 4/2)=290.2 100+ra=290.2 So ra=290.2-100=190.2 pm

Q. A solid $A B$ has $N a Cl$ type structure with edge length $580.4 p m .$ The radius of $A^{+}$ is $100 p m .$ What is the radius of $B^{-}$ in pm?

$190.2$

$540.13$

$525$

$78.12$

$N a Cl$ has fcc structure and thus,
$r_{c} + r_{a} = \frac{a}{2}$
$100 + r_{a} = \frac{580.4}{2} = 290.2$
$100 + r_{a} = 290.2$
So $r_{a} = 290.2 - 100 = 190.2 p m$

Q. A solid AB has NaCl type structure with edge length 580.4pm. The radius of A+ is 100pm. What is the radius of B− in pm?

190.2

540.13

525

78.12