1. Tardigrade
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  3. Chemistry
  4. A solid AB has NaCl type structure with edge length 580.4 pm. The radius of A+ is 100 pm. What is the radius of B- in pm?

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Q. A solid $AB$ has $NaCl$ type structure with edge length $580.4\,pm.$ The radius of $A^{+}$ is $100\,pm.$ What is the radius of $B^{-}$ in pm?

NTA AbhyasNTA Abhyas 2022

Solution:

$NaCl$ has fcc structure and thus,
$r_{c}+r_{a}=\frac{a}{2}$
$100+r_{a}=\frac{580 . 4}{2}=290.2$
$100+r_{a}=290.2$
So $r_{a}=290.2-100=190.2\,pm$