A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current of 5 A is passed through this solenoid, what is the magnetic field inside the solenoid ?

Question

A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current of 5 A is passed through this solenoid, what is the magnetic field inside the solenoid ? (A) 6.28 × 10-4 T (B) 6.28 × 10-1 T (C) 6.28 × 10-7 T (D) 6.28 × 10-5 T

Tardigrade Admin · Accepted Answer

Length of solenoid 1=0.4 cm =0.004 m Number of turn per unit length n =(400/0.004)=105 Magnetic field inside the solenoid B=μ0 nI ∴ B=4 π × 10-7 × 105 × 5=6.28 × 10-1 T

Q. A solenoid has length $0.4 c m$ , radius $1 c m$ and $400 t u r n s$ of wire. If a current of $5 A$ is passed through this solenoid, what is the magnetic field inside the solenoid ?

$6.28 \times 1 0^{- 4} T$

$6.28 \times 1 0^{- 1} T$

$6.28 \times 1 0^{- 7} T$

$6.28 \times 1 0^{- 5} T$

Length of solenoid $1 = 0.4 c m = 0.004 m$
Number of turn per unit length $n = \frac{400}{0.004} = 1 0^{5}$
Magnetic field inside the solenoid $B = μ_{0} n I$
$∴ B = 4 π \times 1 0^{- 7} \times 1 0^{5} \times 5 = 6.28 \times 1 0^{- 1} T$

Q. A solenoid has length 0.4cm, radius 1cm and 400turns of wire. If a current of 5A is passed through this solenoid, what is the magnetic field inside the solenoid ?

6.28×10−4T

6.28×10−1T

6.28×10−7T

6.28×10−5T