A small mass executes SHM around a point O with amplitude A & time period T . Its displacement from O at time T / 8 after passing through O is

Question

A small mass executes SHM around a point O with amplitude A & time period T . Its displacement from O at time T / 8 after passing through O is (A) (A/8) (B) (A/2 √2) (C) (A/2) (D) (A/√2)

Tardigrade Admin · Accepted Answer

Equation of S.H.M. x=Asin ω t ; so when t=T / 8 x=Asin ω × T / 8=Asin â¡ (2 π /T) × (T/8) =Asin (π /4)=(A/√2)

Q. A small mass executes SHM around a point $O$ with amplitude $A$ & time period $T$ . Its displacement from $O$ at time $T /8$ after passing through $O$ is

$\frac{A}{8}$

$\frac{A}{2 2}$

$\frac{A}{2}$

$\frac{A}{2}$

Equation of S.H.M.
$x = A s inω t$ ; so when $t = T /8$
$x = A s inω \times T /8 = A s in {\frac{2 π}{T} \times \frac{T}{8}}$
$= A s in \frac{π}{4} = \frac{A}{2}$

Q. A small mass executes SHM around a point O with amplitude A & time period T . Its displacement from O at time T/8 after passing through O is

8A​

22​A​

2A​

2​A​

Equation of S.H.M. x=Asinωt ; so when t=T/8 x=Asinω×T/8=Asin⁡{T2π​×8T​} =Asin4π​=2​A​

Q. A small mass executes SHM around a point $O$ with amplitude $A$ & time period $T$ . Its displacement from $O$ at time $T /8$ after passing through $O$ is

$\frac{A}{8}$

$\frac{A}{2 2}$

$\frac{A}{2}$

$\frac{A}{2}$

Equation of S.H.M.
$x = A s inω t$ ; so when $t = T /8$
$x = A s inω \times T /8 = A s in {\frac{2 π}{T} \times \frac{T}{8}}$
$= A s in \frac{π}{4} = \frac{A}{2}$