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  4. A small mass executes SHM around a point O with amplitude A & time period T . Its displacement from O at time T / 8 after passing through O is

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Q. A small mass executes SHM around a point $O$ with amplitude $A$ & time period $T$ . Its displacement from $O$ at time $T / 8$ after passing through $O$ is

NTA AbhyasNTA Abhyas 2022

Solution:

Equation of S.H.M.
$x=Asin \omega t$ ; so when $t=T / 8$
$x=Asin \omega \times T / 8=Asin ⁡ \left\{\frac{2 \pi }{T} \times \frac{T}{8}\right\}$
$=Asin \frac{\pi }{4}=\frac{A}{\sqrt{2}}$