A small block is freely sliding down from top of smooth inclined plane. The block reaches bottom o inclined plane then the block describes vertical circle o. radius 0.5 m along smooth track. The minimum vertica height of inclined plane should be

Question

A small block is freely sliding down from top of smooth inclined plane. The block reaches bottom o inclined plane then the block describes vertical circle o. radius 0.5 m along smooth track. The minimum vertica height of inclined plane should be (A) 1 m (B) 1.25 m (C) 3 m (D) 2.5 m

Tardigrade Admin · Accepted Answer

m g h=(1/2) m(5 rg ) ⇒ h=(5 r/2)=(2.5/2)=1.25 m

Q. A small block is freely sliding down from top of smooth inclined plane. The block reaches bottom o inclined plane then the block describes vertical circle o. radius $0.5 m$ along smooth track. The minimum vertica height of inclined plane should be

$1 m$

$1.25 m$

$3 m$

$2.5 m$

$m g h = \frac{1}{2} m (5 r g)$
$\Rightarrow h = \frac{5 r}{2} = \frac{2.5}{2} = 1.25 m$

Q. A small block is freely sliding down from top of smooth inclined plane. The block reaches bottom o inclined plane then the block describes vertical circle o. radius 0.5m along smooth track. The minimum vertica height of inclined plane should be

1m

1.25m

3m

2.5m