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Q. A small block is freely sliding down from top of smooth inclined plane. The block reaches bottom o inclined plane then the block describes vertical circle o. radius $0.5 m$ along smooth track. The minimum vertica height of inclined plane should be

Work, Energy and Power

Solution:

$m g h=\frac{1}{2} m(5 rg ) $
$\Rightarrow h=\frac{5 r}{2}=\frac{2.5}{2}=1.25\, m$