A single letter is selected from the word TRICKS. The probability that it is either T or R is

Question

A single letter is selected from the word TRICKS. The probability that it is either T or R is (A) (1/36) (B) (1/4) (C) (1/2) (D) (2/3)

Tardigrade Admin · Accepted Answer

Number of ways of selecting one letter from the word TRICKS n( S )= 6 C1=6 Let E be the event of selecting T or R ∴ E = T, R ∴ n(E) =2 ∴ Required probability =p(E) =(n(E)/n(S)) =(2/6) =(1/3)

Q. A single letter is selected from the word $TR I C K S$ . The probability that it is either $T$ or $R$ is

$\frac{1}{36}$

$\frac{1}{4}$

$\frac{1}{2}$

$\frac{2}{3}$

$\frac{1}{3}$

Number of ways of selecting one letter from the word TRICKS $n (S) =^{6} C_{1} = 6$
Let $E$ be the event of selecting $T$ or $R$
$∴ E = {T, R}$
$∴ n (E) = 2$
$∴$ Required probability $= p (E)$
$= \frac{n ( E )}{n ( S )}$
$= \frac{2}{6}$
$= \frac{1}{3}$

Q. A single letter is selected from the word TRICKS. The probability that it is either T or R is

361​

41​

21​

32​

31​

Number of ways of selecting one letter from the word TRICKS n(S)=6C1​=6 Let E be the event of selecting T or R ∴E={T,R} ∴n(E)=2 ∴ Required probability =p(E) =n(S)n(E)​ =62​ =31​