Question

A single letter is selected from the word $TRICKS$. The probability that it is either $T$ or $R$ is

• A. $\frac{1}{36}$
• B. $\frac{1}{4}$
• C. $\frac{1}{2}$
• D. $\frac{2}{3}$
• E. $\frac{1}{3}$

Answer 1

Answer: (E)

Number of ways of selecting one letter from the word TRICKS $n( S )={ }^{6} C_{1}=6$
Let $E$ be the event of selecting $T$ or $R$
$\therefore E =\{T, R\} $
$\therefore n(E) =2$
$\therefore $ Required probability $=p(E)$
$=\frac{n(E)}{n(S)} $
$=\frac{2}{6} $
$=\frac{1}{3}$