Question

A simple harmonic motion is given by $y=5(sin3\pi t+\sqrt{3}cos3\pi t)$ . What is the amplitude of motion if $y$ is in cm :-

• A. $100cm$
• B. $5m$
• C. $200cm$
• D. $10cm$

Answer 1

Answer: (D)

$\varphi =90^{\circ }$
so $A=\sqrt{5^2+{\left(5\sqrt{3}\right)}^2}=5\times 2=10cm$