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  4. A simple harmonic motion is given by y=5(.sin3π t+√3cos3π t.) . What is the amplitude of motion if y is in cm :-

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Q. A simple harmonic motion is given by $y=5\left(\right.sin3\pi t+\sqrt{3}cos3\pi t\left.\right)$ . What is the amplitude of motion if $y$ is in cm :-

NTA AbhyasNTA Abhyas 2020

Solution:

$\phi=90^\circ $
so $A=\sqrt{5^{2} + \left(5 \sqrt{3}\right)^{2}}=5\times 2=10cm$