A silicon and germanium diode is connected in series as shown below The current flowing through the circuit will be

Question

A silicon and germanium diode is connected in series as shown below <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6a2a19ac7ba884820d615724ebe1f6f0-.png" /> The current flowing through the circuit will be (A) 6 A (B) 3 A (C) 2 A (D) 1 A

Tardigrade Admin · Accepted Answer

We know that, barrier potential of G e, VB1=0.3 V and barrier potential of S i, VB2=0.7 V Redrawing the above figure as <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/544d3a3d8b9f4cb145069ef96c68cd95-.png" /> Applying KVL, we get -19+0.3+1 ⋅ I+0.7+2 I=0 ⇒ 3 I=18 ⇒ I=6 A

Q. A silicon and germanium diode is connected in series as shown below

The current flowing through the circuit will be

6 A$

$3 A$

$2 A$

$1 A$

We know that, barrier potential of $G e, V_{B_{1}} = 0.3 V$ and barrier potential of $S i, V_{B_{2}} = 0.7 V$
Redrawing the above figure as

Applying KVL, we get
$- 19 + 0.3 + 1 \cdot I + 0.7 + 2 I = 0$
$\Rightarrow 3 I = 18 \Rightarrow I = 6 A$

Q. A silicon and germanium diode is connected in series as shown below The current flowing through the circuit will be