A saturated solution of Ag 2 SO 4 is 2.5 × 10-2 M. The value of its solubility product is

Question

A saturated solution of Ag 2 SO 4 is 2.5 × 10-2 M. The value of its solubility product is (A)  62.5× 10-6  (B)  62.5× 10-4  (C)  15.625× 10-6 (D)  3.125× 10-6

Tardigrade Admin · Accepted Answer

Given, solubility of Ag 2 SO 4=2.5 × 10-2 M Let the solution of Ag 2 SO 4=x mol / L undersetxA g2 S O4 arrow 2 underset2 x2 A g++ undersetxS O42- Ks p=[A g+][S O42-] =(2 x)2(x)=4 x3 =4 ×(2.5 × 10-2)3 =62.5 × 10-6

Q. A saturated solution of $A g_{2} S O_{4}$ is $2.5 \times 1 0^{- 2} M$ . The value of its solubility product is

$62.5 \times 10^{- 6}$

$62.5 \times 10^{- 4}$

$15.625 \times 10^{- 6}$

$3.125 \times 10^{- 6}$

Q. A saturated solution of Ag2​SO4​ is 2.5×10−2M. The value of its solubility product is

62.5×10−6

62.5×10−4

15.625×10−6

3.125×10−6

Given, solubility of Ag2​SO4​=2.5×10−2M Let the solution of Ag2​SO4​=xmol/L xAg2​SO​4​→22x2Ag+​+xSO42−​​ Ksp​=[Ag+][SO42−​] =(2x)2(x)=4x3 =4×(2.5×10−2)3 =62.5×10−6

Q. A saturated solution of $A g_{2} S O_{4}$ is $2.5 \times 1 0^{- 2} M$ . The value of its solubility product is

$62.5 \times 10^{- 6}$

$62.5 \times 10^{- 4}$

$15.625 \times 10^{- 6}$

$3.125 \times 10^{- 6}$