Question

A saturated solution of $Ag _{2} SO _{4}$ is $2.5 \times 10^{-2} M$. The value of its solubility product is

• A. $ 62.5\times {10}^{-6} $
• B. $ 62.5\times {10}^{-4} $
• C. $ 15.625\times {10}^{-6}$
• D. $ 3.125\times {10}^{-6} $

Answer 1

Answer: (A)

Given, solubility of $Ag _{2} SO _{4}=2.5 \times 10^{-2} M$
Let the solution of $Ag _{2} SO _{4}=x mol / L$
$\underset{x}{A g_{2} S O}_{4} \rightarrow 2 \underset{2 x}{2 A g^{+}}+\underset{x}{S O_{4}^{2-}}$
$K_{s p}=\left[A g^{+}\right]\left[S O_{4}^{2-}\right]$
$=(2 x)^{2}(x)=4 x^{3}$
$=4 \times\left(2.5 \times 10^{-2}\right)^{3}$
$=62.5 \times 10^{-6}$