A satellite which is geostationary in a particular orbit is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is :

Question

A satellite which is geostationary in a particular orbit is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is : (A) 24 h (B) 48 h (C) 48√2 h (D)  (48/√2) h

Tardigrade Admin · Accepted Answer

T2 propto r3 (T1/T2)=((r1/r2))3 / 2; (24 h/T)=((r/2 r))3 / 2 T=24(2 √2); T=48√2h

Q. A satellite which is geostationary in a particular orbit is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is :

$24 h$

$48 h$

$482 h$

$\frac{48}{2} h$

$T^{2} \propto r^{3}$
$\frac{T _{1}}{T _{2}} = (\frac{r _{1}}{r _{2}})^{3/2}; \frac{24 h}{T} = (\frac{r}{2 r})^{3/2}$
$T = 24 (22); T = 482 h$

Q. A satellite which is geostationary in a particular orbit is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is :

24h

48h

482​h

2​48​h

T2∝r3 T2​T1​​=(r2​r1​​)3/2;T24h​=(2rr​)3/2 T=24(22​);T=482​h

$24 h$

$48 h$

$482 h$

$\frac{48}{2} h$

$T^{2} \propto r^{3}$
$\frac{T _{1}}{T _{2}} = (\frac{r _{1}}{r _{2}})^{3/2}; \frac{24 h}{T} = (\frac{r}{2 r})^{3/2}$
$T = 24 (22); T = 482 h$