Question

A satellite which is geostationary in a particular orbit is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is :

• A. $24 \, h$
• B. $48 \, h$
• C. $48\sqrt{2} \, h$
• D. $ \, \frac{48}{\sqrt{2}} \, h$

Answer 1

Answer: (C)

$T^{2} \propto \, r^{3}$
$\frac{T_{1}}{T_{2}}=\left(\frac{r_{1}}{r_{2}}\right)^{3 / 2}; \, \frac{24 h}{T}=\left(\frac{r}{2 r}\right)^{3 / 2}$
$T=24\left(2 \sqrt{2}\right); \, T=48\sqrt{2}h$