A sample of gas occupies 10 L under a pressure of 1 atm. What will be its volume if the pressure is increased to 2 atm ? Assuming that temperature of the gas sample does not change,

Question

A sample of gas occupies 10 L under a pressure of 1 atm. What will be its volume if the pressure is increased to 2 atm ? Assuming that temperature of the gas sample does not change, (A) 2 L (B) 5 L (C) 10 L (D) 1 L

Tardigrade Admin · Accepted Answer

Given: P1 =1 atm ; V 1=10 L P 2 =2 atm Then, applying Boyle's Law, P1 V1=P2 V2 or, V2=(P1 V1/P2) =(1 a t m × 10 L/2 a t m)=5 L

Q. A sample of gas occupies $10 L$ under a pressure of $1 a t m$ . What will be its volume if the pressure is increased to $2 a t m$ ? Assuming that temperature of the gas sample does not change,

2 L

5 L

10 L

1 L

Given: $P_{1} = 1 a t m; V_{1} = 10 L$
$P_{2} = 2 a t m$
Then, applying Boyle's Law,
$P_{1} V_{1} = P_{2} V_{2}$
or, $V_{2} = \frac{P _{1} V _{1}}{P _{2}}$
$= \frac{1 a t m \times 10 L}{2 a t m} = 5 L$

Q. A sample of gas occupies 10L under a pressure of 1atm. What will be its volume if the pressure is increased to 2atm ? Assuming that temperature of the gas sample does not change,

2 L

5 L

10 L

1 L

Given: P1​=1atm;V1​=10L P2​=2atm Then, applying Boyle's Law, P1​V1​=P2​V2​ or, V2​=P2​P1​V1​​ =2atm1atm×10L​=5L

Q. A sample of gas occupies $10 L$ under a pressure of $1 a t m$ . What will be its volume if the pressure is increased to $2 a t m$ ? Assuming that temperature of the gas sample does not change,

Given: $P_{1} = 1 a t m; V_{1} = 10 L$
$P_{2} = 2 a t m$
Then, applying Boyle's Law,
$P_{1} V_{1} = P_{2} V_{2}$
or, $V_{2} = \frac{P _{1} V _{1}}{P _{2}}$
$= \frac{1 a t m \times 10 L}{2 a t m} = 5 L$