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Q. A sample of gas occupies $10\, L$ under a pressure of $1\, atm$. What will be its volume if the pressure is increased to $2\, atm$ ? Assuming that temperature of the gas sample does not change,

States of Matter

Solution:

Given: $P_{1} =1\, atm ; V _{1}=10\, L $
$P _{2} =2 \,atm $
Then, applying Boyle's Law,
$P_{1} V_{1}=P_{2} V_{2} $
or, $ V_{2}=\frac{P_{1} V_{1}}{P_{2}}$
$=\frac{1 a t m \times 10 L}{2 a t m}=5 L$