Question

A root of the equation $\Delta =\left|\begin{array}{ccc}0& x-a& x-b\\ x+a& 0& x-c\\ x+b& x+c& 0\end{array}\right|=0\text{ i }$

• A. $\frac{1}{2}(a+b+c)$
• B. 0
• C. -1
• D. 1

Answer 1

Answer: (B)

When we substitute $x=0,\Delta$ becomes
$\left|\begin{array}{ccc}0& -a& -b\\ a& 0& -c\\ b& c& 0\end{array}\right|$
which is equal to 0 as $\Delta$ is skew symmetric determinant of odd order.