Thank you for reporting, we will resolve it shortly
Q.
A root of the equation
$\Delta=\begin{vmatrix}
0 & x-a & x-b \\
x+a & 0 & x-c \\
x+b & x+c & 0
\end{vmatrix}=0 \text { i }$
Determinants
Solution:
When we substitute $x=0, \Delta$ becomes
$\begin{vmatrix}0 & -a & -b \\a & 0 & -c \\b & c & 0\end{vmatrix}$
which is equal to 0 as $\Delta$ is skew symmetric determinant of odd order.