A rod of length 20 cm is rotating with angular speed of 100 rps in a magnetic field of strength 0.5 T about its one end. What is the potential difference between two ends of the rod?

Question

A rod of length 20 cm is rotating with angular speed of 100 rps in a magnetic field of strength 0.5 T about its one end. What is the potential difference between two ends of the rod? (A) 2.28 V (B) 4.28 V (C) 6.28 V (D) 2.5 V

Tardigrade Admin · Accepted Answer

e=(1/2) B l2 ω=B l2 π v e=0.5(20 × 10-2)2 × 3.14 × 100=6.28 V

Q. A rod of length $20 c m$ is rotating with angular speed of $100 r p s$ in a magnetic field of strength $0.5 T$ about its one end. What is the potential difference between two ends of the rod?

2.28 V

4.28 V

6.28 V

2.5 V

$e = \frac{1}{2} B l^{2} ω = B l^{2} π v$
$e = 0.5 (20 \times 1 0^{- 2})^{2} \times 3.14 \times 100 = 6.28 V$

Q. A rod of length 20cm is rotating with angular speed of 100rps in a magnetic field of strength 0.5T about its one end. What is the potential difference between two ends of the rod?