Question

A rod of length $20\, cm$ is rotating with angular speed of $100\, rps$ in a magnetic field of strength $0.5\, T$ about its one end. What is the potential difference between two ends of the rod?

• A. 2.28 V
• B. 4.28 V
• C. 6.28 V
• D. 2.5 V

Answer 1

Answer: (C)

$e=\frac{1}{2} B l^{2} \omega=B l^{2} \pi v$
$e=0.5\left(20 \times 10^{-2}\right)^{2} \times 3.14 \times 100=6.28\, V$