A rod of length 20 cm is rotating with angular speed of 100 revolutions per minute in a magnetic field of strength 0.5 T. What is the potential difference between two ends of the rod?

Question

A rod of length 20 cm is rotating with angular speed of 100 revolutions per minute in a magnetic field of strength 0.5 T. What is the potential difference between two ends of the rod? (A) 2.28 V (B) 4.28 V (C) 6.28 V (D) 0.105 V

Tardigrade Admin · Accepted Answer

V=(1/2) B L2 ω =(1/2) × (1/2) ×(0.2)2 × 2 π × (100/60)=(2 π/60)=0.105 V

Q. A rod of length $20 c m$ is rotating with angular speed of $100$ revolutions per minute in a magnetic field of strength $0.5 T$ . What is the potential difference between two ends of the rod?

2.28 V

4.28 V

6.28 V

0.105 V

$V = \frac{1}{2} B L^{2} ω$
$= \frac{1}{2} \times \frac{1}{2} \times (0.2)^{2} \times 2 π \times \frac{100}{60} = \frac{2 π}{60} = 0.105 V$

Q. A rod of length 20cm is rotating with angular speed of 100 revolutions per minute in a magnetic field of strength 0.5T. What is the potential difference between two ends of the rod?