A ring of radius R rolls without slipping on a rough horizontal surface with a constant velocity. The radius of curvature of the path followed by any particle of the ring at the highest point of its path will be:

Question

A ring of radius R rolls without slipping on a rough horizontal surface with a constant velocity. The radius of curvature of the path followed by any particle of the ring at the highest point of its path will be: <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-zixrtatczxgp.png" /> (A) 5 R (B) 2 R (C) 4 R (D) None of these

Tardigrade Admin · Accepted Answer

Radius of Curvature = (( textvelocity)2/ textNormal Acceleration) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-zixrtatc2ar6.png" /> =((2 v )2/ v 2 / R )=4 R

Q. A ring of radius R rolls without slipping on a rough horizontal surface with a constant velocity. The radius of curvature of the path followed by any particle of the ring at the highest point of its path will be :

5 R

2 R

4 R

None of these

Radius of Curvature
$= \frac{( velocity ) ^{2}}{Normal Acceleration}$

$= \frac{( 2 v ) ^{2}}{v ^{2} / R} = 4 R$

Q. A ring of radius R rolls without slipping on a rough horizontal surface with a constant velocity. The radius of curvature of the path followed by any particle of the ring at the highest point of its path will be :

5 R

2 R

4 R

None of these

Radius of Curvature =Normal Acceleration(velocity)2​ =v2/R(2v)2​=4R

Radius of Curvature
$= \frac{( velocity ) ^{2}}{Normal Acceleration}$

$= \frac{( 2 v ) ^{2}}{v ^{2} / R} = 4 R$