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Q. A ring of radius R rolls without slipping on a rough horizontal surface with a constant velocity. The radius of curvature of the path followed by any particle of the ring at the highest point of its path will be :

Question

NTA AbhyasNTA Abhyas 2020System of Particles and Rotational Motion

Solution:

Radius of Curvature
$= \frac{\left(\text{velocity}\right)^{2}}{\text{Normal Acceleration}}$
Solution
$=\frac{(2 v )^{2}}{ v ^{2} / R }=4 R$