A resistance of 40 ohm and an inductance of 95.5 millihenry are connected in series in a 50 cycles/second AC circuit. The impedance of this combination is very nearly

Question

A resistance of 40 ohm and an inductance of 95.5 millihenry are connected in series in a 50 cycles/second AC circuit. The impedance of this combination is very nearly (A) 30 ohm (B) 40 ohm (C) 50 ohm (D) 60 ohm

Tardigrade Admin · Accepted Answer

Z=√R2+(2 π v L)2 =√(40)2+4 π2 ×(50)2 ×(95.5 × 10-3)2=50 ohm

Q. A resistance of $40$ ohm and an inductance of $95.5$ millihenry are connected in series in a $50$ cycles/second AC circuit. The impedance of this combination is very nearly

30 ohm

40 ohm

50 ohm

60 ohm

$Z = R^{2} + (2 π vL)^{2}$
$= (40)^{2} + 4 π^{2} \times (50)^{2} \times (95.5 \times 1 0^{- 3})^{2} = 50$ ohm

Q. A resistance of 40 ohm and an inductance of 95.5 millihenry are connected in series in a 50 cycles/second AC circuit. The impedance of this combination is very nearly