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  4. A resistance of 40 ohm and an inductance of 95.5 millihenry are connected in series in a 50 cycles/second AC circuit. The impedance of this combination is very nearly

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Q. A resistance of $40$ ohm and an inductance of $95.5$ millihenry are connected in series in a $50$ cycles/second AC circuit. The impedance of this combination is very nearly

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Solution:

$Z=\sqrt{R^{2}+(2 \pi v L)^{2}}$
$=\sqrt{(40)^{2}+4 \pi^{2} \times(50)^{2} \times\left(95.5 \times 10^{-3}\right)^{2}}=50$ ohm