A research satellite of mass 200 kg circles the earth in an orbit of average radius (3R/2) where R is the radius of earth. Assuming the gravitatioaal pull on a mass of 1 kg on the earth's surface to be 10 N, the puII on the sateIlite will be

Question

A research satellite of mass 200 kg circles the earth in an orbit of average radius (3R/2) where R is the radius of earth. Assuming the gravitatioaal pull on a mass of 1 kg on the earth's surface to be 10 N, the puII on the sateIlite will be (A) 880 N (B) 889 N (C) 885 N (D) 892 N

Tardigrade Admin · Accepted Answer

On earth, mg= 10 or 1 × g = 10 ⇒ g = 10 ms-2 Now, g' = g(R2/r2) = 10 × (R2/(3R/2)2)=(40/9) Pull on satellite = m' g' = 200 × (40/9) = 889 N

Q. A research satellite of mass $200 k g$ circles the earth in an orbit of average radius $\frac{3 R}{2}$ where $R$ is the radius of earth. Assuming the gravitatioaal pull on a mass of $1 k g$ on the earth's surface to be $10 N$ , the puII on the sateIlite will be

880 N

889 N

885 N

892 N

On earth, $m g = 10 or 1 \times g = 10$
$\Rightarrow g = 10 m s^{- 2}$
Now, $g^{'} = g \frac{R ^{2}}{r ^{2}} = 10 \times \frac{R ^{2}}{( 3 R /2 ) ^{2}} = \frac{40}{9}$
Pull on satellite = m' g'
$= 200 \times \frac{40}{9} = 889 N$

Q. A research satellite of mass 200kg circles the earth in an orbit of average radius 23R​ where R is the radius of earth. Assuming the gravitatioaal pull on a mass of 1kg on the earth's surface to be 10N, the puII on the sateIlite will be