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Q. A research satellite of mass $200\, kg$ circles the earth in an orbit of average radius $\frac{3R}{2}$ where $R$ is the radius of earth. Assuming the gravitatioaal pull on a mass of $1\, kg$ on the earth's surface to be $10\, N$, the puII on the sateIlite will be

Gravitation

Solution:

On earth,$ mg= 10\, or\, 1 \times g = 10$
$\Rightarrow g = 10\, ms^{-2}$
Now, $g' = g\frac{R^2}{r^2} = 10 \times \frac{R^2}{(3R/2)^2}=\frac{40}{9}$
Pull on satellite = m' g'
$= 200 \times \frac{40}{9} = 889\, N$