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Tardigrade
Question
Physics
A rectangular block is heated from 0°C to 100°C. The percentage increase in its length is 0.2 %. The percentage increase in its volume is
Q. A rectangular block is heated from
0
∘
C
to
10
0
∘
C
. The percentage increase in its length is
0.2%
. The percentage increase in its volume is
4414
200
Thermal Properties of Matter
Report Error
A
0.6%
37%
B
0.10%
13%
C
0.2%
25%
D
0.4%
25%
Solution:
Volume
V
=
L
3
∴
V
Δ
V
×
100
=
3
L
Δ
L
×
100
=
3
×
0.2%
=
0.6%
(
∵
L
Δ
L
=
0.2
)