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Physics
A rectangular block is heated from 0°C to 100°C. The percentage increase in its length is 0.2 %. The percentage increase in its volume is
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Q. A rectangular block is heated from $0^{\circ}C$ to $100^{\circ}C$. The percentage increase in its length is $0.2\%$. The percentage increase in its volume is
Thermal Properties of Matter
A
$0.6\%$
37%
B
$0.10\%$
13%
C
$0.2\%$
25%
D
$0.4\%$
25%
Solution:
Volume $V= L^3$
$\therefore \frac{\Delta V}{V} \times 100=3 \frac{\Delta L}{L} \times100$
$=3 \times 0.2\%=0.6\% \quad $$\left(\because \frac{\Delta L}{L}=0.2\right)$