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Q. A rectangular block is heated from $0^{\circ}C$ to $100^{\circ}C$. The percentage increase in its length is $0.2\%$. The percentage increase in its volume is

Thermal Properties of Matter

Solution:

Volume $V= L^3$
$\therefore \frac{\Delta V}{V} \times 100=3 \frac{\Delta L}{L} \times100$
$=3 \times 0.2\%=0.6\% \quad $$\left(\because \frac{\Delta L}{L}=0.2\right)$