A rectangle is inscribed in a circle with a diameter lying along the line 3y = x + 7. If the two adjacent vertices of the rectangle are (-8, 5) and (6, 5), then the area of the rectangle (in sq. units) is :

Question

A rectangle is inscribed in a circle with a diameter lying along the line 3y = x + 7. If the two adjacent vertices of the rectangle are (-8, 5) and (6, 5), then the area of the rectangle (in sq. units) is : (A) 72 (B) 84 (C) 98 (D) 56

Tardigrade Admin · Accepted Answer

(3(a+5)/2) = -1+7 a+5 = (2(6)/3) a = - 1 sides = 6 and 14 ⇒ A = 84

Q. A rectangle is inscribed in a circle with a diameter lying along the line $3 y = x + 7$ . If the two adjacent vertices of the rectangle are $(- 8, 5)$ and $(6, 5)$ , then the area of the rectangle (in sq. units) is :

72

84

98

56

$\frac{3 ( a + 5 )}{2} = - 1 + 7$
$a + 5 = \frac{2 ( 6 )}{3}$
$a = - 1$
sides = $6$ and $14$
$\Rightarrow A = 84$

Q. A rectangle is inscribed in a circle with a diameter lying along the line 3y=x+7. If the two adjacent vertices of the rectangle are (−8,5) and (6,5), then the area of the rectangle (in sq. units) is :

72

84

98

56

23(a+5)​=−1+7 a+5=32(6)​ a=−1 sides = 6 and 14 ⇒A=84

Q. A rectangle is inscribed in a circle with a diameter lying along the line $3 y = x + 7$ . If the two adjacent vertices of the rectangle are $(- 8, 5)$ and $(6, 5)$ , then the area of the rectangle (in sq. units) is :

$\frac{3 ( a + 5 )}{2} = - 1 + 7$
$a + 5 = \frac{2 ( 6 )}{3}$
$a = - 1$
sides = $6$ and $14$
$\Rightarrow A = 84$