Q. A rectangle is inscribed in a circle with a diameter lying along the line $3y = x + 7$. If the two adjacent vertices of the rectangle are $(-8, 5)$ and $(6, 5)$, then the area of the rectangle (in sq. units) is :
Solution:
$\frac{3\left(a+5\right)}{2} = -1+7 $
$ a+5 = \frac{2\left(6\right)}{3} $
$a = - 1$
sides = $6$ and $14$
$ \Rightarrow A = 84 $