Q. A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are $n \times 1 0^{- 1}$ , when n = (Round off to the Nearest Integer).
(Given : Atomic masses : $C : 12.0 u, H : 1.0 u, N : 14.0 u, B r : 80.0 u$ ]

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Answer: 3

Solution:

Q. A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are n×10−1, when n = (Round off to the Nearest Integer). (Given : Atomic masses : C:12.0u,H:1.0u,N:14.0u,Br:80.0u ]